document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033128>Question 1033128</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y=(-1/2)x^2-6 was the result of shifting down 5 units, what was the original function? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647709 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647709\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i believe the original equation must have been y = (-1/2)x^2 - 1.\r<BR>\n" );
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document.write( "from that original equation, the equation of y = (-1/2)x^2 - 6 will be 5 units below it.\r<BR>\n" );
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document.write( "the following graph shows the relationship.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2016/050502.jpg\" alt=\"$$$\" </><BR>\n" );
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