document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033112>Question 1033112</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Vehicle A and B, moving at a constant velocities, are 8km apart at the starting time of 3:40pm. If after 40 mins, Vehicle B overtakes A, at what time will they be 10 km apart?\r<BR>\n" );
document.write( "\n" );
document.write( "Is there a strategy to do these problems? Plus, it seems like they are only a few numerical values. How do I deal with these problems as well? Thank you very much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647703 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647703\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let speed of B be x km/h<BR>\n" );
document.write( "and that of A = y\r<BR>\n" );
document.write( "\n" );
document.write( "after 2/3 hour B&A are together \r<BR>\n" );
document.write( "\n" );
document.write( "catchup speed *catchup time =8\r<BR>\n" );
document.write( "\n" );
document.write( "catchup speed = x-y\r<BR>\n" );
document.write( "\n" );
document.write( "catchup time = 2/3<BR>\n" );
document.write( "d=8\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2/3(x-y) =8\r<BR>\n" );
document.write( "\n" );
document.write( "x-y =12\r<BR>\n" );
document.write( "\n" );
document.write( "d=10<BR>\n" );
document.write( "let t be the time they are 10 km apart\r<BR>\n" );
document.write( "\n" );
document.write( "t(x-y) = 10\r<BR>\n" );
document.write( "\n" );
document.write( "12t = 10\r<BR>\n" );
document.write( "\n" );
document.write( "t = 10/12 = 5/6 \r<BR>\n" );
document.write( "\n" );
document.write( "5/6 +2/3 = 9/6 = 1.5 hours\r<BR>\n" );
document.write( "\n" );
document.write( "3:40 +1:30 = 5:10 pm\r<BR>\n" );
document.write( "\n" );
document.write( "At 5:10 they are 10 km apart<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );