document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033095>Question 1033095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is twice as old as his son<BR>\n" );
document.write( "2.1if the sons age is represented by x how old is the father<BR>\n" );
document.write( "2.2how old were the father and son 20years back<BR>\n" );
document.write( "2.3   20years ago the father was six times his sons age represent this as an equation </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647683 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647683\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So the father is twice, meaning two times, older than the son. In algebraic terms: f = 2s Since the problem says that x stands for the son's age, substitute s with x and you have your answer.<BR>\n" );
document.write( "f-20 = 2s-20<BR>\n" );
document.write( "f-20 = 6(son-20) <BR>\n" );
document.write( "Remember to substitute for x </SPAN>\n" );
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