document.write( "Question 1033073: Deandre's boat has a top speed of
\n" ); document.write( "10
\n" ); document.write( " miles per hour in still water. While traveling on a river at top speed, he went
\n" ); document.write( "16
\n" ); document.write( " miles upstream in the same amount of time he went
\n" ); document.write( "24
\n" ); document.write( " miles downstream. Find the rate of the river current.
\n" ); document.write( "

Algebra.Com's Answer #647671 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+c+\" = the speed of the current in mi/hr
\n" ); document.write( "\"+10+%2B+c+\" = boat's speed going downstream in mi/hr
\n" ); document.write( "\"+10+-+c+\" = boat's speed going upstream in mi/hr
\n" ); document.write( "Let \"+t+\" = time in hrs for both trips
\n" ); document.write( "--------------------------------
\n" ); document.write( "Equation for going downstream:
\n" ); document.write( "(1) \"+24+=+%28+10+%2B+c+%29%2At+\"
\n" ); document.write( "Equation for going upstream:
\n" ); document.write( "(2) \"+16+=+%28+10+-+c+%29%2At+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "(1) \"+t+=+24+%2F+%28+10+%2B+c+%29+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+16+=+%28+10+-+c+%29%2A%28+24+%2F+%28+10+%2B+c+%29+%29+\"
\n" ); document.write( "(2) \"+16%2A%28+10+%2B+c+%29+=+24%2A%28+10+-+c+%29+\"
\n" ); document.write( "(2) \"+160+%2B+16c+=+240+-+24c+\"
\n" ); document.write( "(2) \"+40c+=+80+\"
\n" ); document.write( "(2) \"+c+=+2+\"
\n" ); document.write( "The rate of the current is 2 mi/hr
\n" ); document.write( "--------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+24+=+%28+10+%2B+2+%29%2At+\"
\n" ); document.write( "(1) \"+t+=+24+%2F+12+\"
\n" ); document.write( "(1) \"+t+=+2+\" hrs
\n" ); document.write( "and
\n" ); document.write( "(2) \"+16+=+%28+10+-+2+%29%2At+\"
\n" ); document.write( "(2) \"+16+=+8t+\"
\n" ); document.write( "(2) \"+t+=+2+\" hrs
\n" ); document.write( "OK
\n" ); document.write( "
\n" );