document.write( "Question 1032869: Lala can remove the engine from a car in 4 hours. George can do it in 3 hours. George starts the job alone. One hour later, Lala begins helping him. How long will Lala work before the engine is out? \n" ); document.write( "
Algebra.Com's Answer #647668 by josmiceli(19441) You can put this solution on YOUR website! George's rate of working: [ 1 engine removed ] / [ 3 hrs ] \n" ); document.write( "In 1 hr, the fraction of the job that George gets done is: \n" ); document.write( " \n" ); document.write( "That means 2/3 of the job is left to do \n" ); document.write( "----------------------- \n" ); document.write( "Lala's rate of working: [ 1 engine removed ] / [ 4 hrs ] \n" ); document.write( "Now they work together to do the remaining 2/3 of the job \n" ); document.write( "Let \n" ); document.write( "Add their rates of working: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Lala will work 1 hr 8 min 34 sec before engine is out \n" ); document.write( "-------------------------- \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |