document.write( "Question 1032985: \"if you add the number 2 to the beginning and the end of a 2-digit, natural number, then the product of the digits in your number is 2222 times larger than your original number\" \n" ); document.write( "
Algebra.Com's Answer #647651 by Edwin McCravy(20065)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Something's wrong with the problem or else I am interpreting \r\n" );
document.write( "it wrong.  \r\n" );
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document.write( "1. Suppose the 2-digit number were very large, say 99, the \r\n" );
document.write( "largest 2-digit number. then if you added a 2 on each end,\r\n" );
document.write( "you'd have 2992, but the product of the digits would be only\r\n" );
document.write( "2*9*9*2 = 324, but 2222 times the original number 99 is 219978, \r\n" );
document.write( "much larger than 324.\r\n" );
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document.write( "2. Suppose the 2-digit number were very small,\r\n" );
document.write( "say 11, a small 2-digit number.  Then if you added a 2 on each \r\n" );
document.write( "end, you'd have 2112, but the product of the digits would be \r\n" );
document.write( "only 2*1*1*2 = 4, but 2222 times the original number 11 is \r\n" );
document.write( "24442, much larger than 4.\r\n" );
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document.write( "With this interpretation, there can be no solution.  If I am \r\n" );
document.write( "interpreting it incorrectly, then you may tell me the correct \r\n" );
document.write( "way to interpret it in the thank-you note form below and I'll \r\n" );
document.write( "get back to you by email.\r\n" );
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document.write( "Edwin
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