document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032963>Question 1032963</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Express the value as a trigonometric function of an angle in Quadrant 1.<BR>\n" );
document.write( "cot([125pi]/[8]) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647561 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Express the value as a trigonometric function of an angle in Quadrant 1.<BR>\n" );
document.write( "cot([125pi]/[8]) <BR>\n" );
document.write( "----<BR>\n" );
document.write( "Find the number of 2pi sets to subtract::\r<BR>\n" );
document.write( "\n" );
document.write( "[125pi/8] / (2pi) = (125/16) = 7.8125<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "125pi/8 - 7(2pi) = 1.625pi = 1 5/8 pi is in QIV where cot is negative<BR>\n" );
document.write( "----<BR>\n" );
document.write( "reference angle = 2pi - 1 5/8 pi = 3/8 pi<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Ans: cot[(125/8)pi]-cot(3/8 pi)<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );