document.write( "Question 1032953: What's the probability of at least one 3 in 10 rolls of a fair die? \n" ); document.write( "
Algebra.Com's Answer #647542 by FrankM(1040) You can put this solution on YOUR website! This simplifies to 1-P(no 3s)\r \n" ); document.write( "\n" ); document.write( "the probability of each roll being not 3 is 5/6, for 10 rolls, (5/6)^10 or .1615, 16.15% , a bit less than 1 in 6. But this is for no 3s.\r \n" ); document.write( "\n" ); document.write( "1-.1615= .8385 or 83.85% \n" ); document.write( " |