document.write( "Question 89080: Tutor could you help me please...thank you\r
\n" ); document.write( "\n" ); document.write( "10square root3 -7square root3+5square root3=\r
\n" ); document.write( "\n" ); document.write( " Would the answer be:\r
\n" ); document.write( "\n" ); document.write( " -2square root 3
\n" ); document.write( " -3square root 3
\n" ); document.write( " 8square root 3
\n" ); document.write( " or
\n" ); document.write( " 12square root 3
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Algebra.Com's Answer #64752 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
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\n" ); document.write( "\"10%2Asqrt%283%29+-+7%2Asqrt%283%29+%2B+5%2Asqrt%283%29\"
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\n" ); document.write( "To combine these terms just combine the multipliers of \"sqrt%283%29\" and multiply the
\n" ); document.write( "result of this combination by \"sqrt%283%29\" to give you \"8%2Asqrt%283%29\".
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\n" ); document.write( "Another way of looking at the problem is that since every one of the terms has \"sqrt%283%29\"
\n" ); document.write( "as a factor it can be factored out. The result is:
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\n" ); document.write( "\"sqrt%283%29%2A%2810+-+7+%2B+5%29\"
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\n" ); document.write( "Then combine the terms inside the parentheses. 10 - 7 + 5 = +8. So you can replace the three
\n" ); document.write( "terms in the parentheses by +8 and the problem becomes:
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\n" ); document.write( "\"sqrt%283%29%2A%288%29\"
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\n" ); document.write( "and by convention we normally write this in the reverse order: \"8%2Asqrt%283%29\".
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\n" ); document.write( "Therefore, the third answer in your list of answers is the correct one ...
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\n" ); document.write( "Hope this helps you to understand the problem.
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