document.write( "Question 1032705:
\n" ); document.write( "Four times
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\n" ); document.write( "a first number decreased by a second number is 25
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\n" ); document.write( "The first number increased by three times
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\n" ); document.write( "the second number is 16
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\n" ); document.write( "Find the numbers
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Algebra.Com's Answer #647476 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
let a = the first number
\n" ); document.write( "let b = the 2nd number
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\n" ); document.write( "Write an equation for each statement
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\n" ); document.write( "Four times a first number decreased by a second number is 25.
\n" ); document.write( "4a - b = 25
\n" ); document.write( "The first number increased by three times the second number is 16
\n" ); document.write( "a + 3b = 16
\n" ); document.write( "a = -3b + 16; use this for substitution in the 1st equation
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\n" ); document.write( "4(-3b+16) - b = 25
\n" ); document.write( "-12b + 64 - b = 25
\n" ); document.write( "-12b - b = 25 - 64
\n" ); document.write( "-13b = -39
\n" ); document.write( "b = -39/-13
\n" ); document.write( "b = +3
\n" ); document.write( "Find a
\n" ); document.write( "a = -3(3) + 16
\n" ); document.write( "a = -9 + 16
\n" ); document.write( "a = 7
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\n" ); document.write( "Find the numbers 7 & 3
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\n" ); document.write( "Check this in the 1st statement
\n" ); document.write( "\"Four times a first number decreased by a second number is 25\"
\n" ); document.write( "4(7) - 3 = 25
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