document.write( "Question 1032705:
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document.write( "Four times
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document.write( "a first number decreased by a second number is 25
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document.write( "The first number increased by three times
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document.write( "the second number is 16
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document.write( "Find the numbers \n" );
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Algebra.Com's Answer #647476 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let a = the first number \n" ); document.write( "let b = the 2nd number \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "Four times a first number decreased by a second number is 25. \n" ); document.write( "4a - b = 25 \n" ); document.write( "The first number increased by three times the second number is 16 \n" ); document.write( "a + 3b = 16 \n" ); document.write( "a = -3b + 16; use this for substitution in the 1st equation \n" ); document.write( ": \n" ); document.write( "4(-3b+16) - b = 25 \n" ); document.write( "-12b + 64 - b = 25 \n" ); document.write( "-12b - b = 25 - 64 \n" ); document.write( "-13b = -39 \n" ); document.write( "b = -39/-13 \n" ); document.write( "b = +3 \n" ); document.write( "Find a \n" ); document.write( "a = -3(3) + 16 \n" ); document.write( "a = -9 + 16 \n" ); document.write( "a = 7 \n" ); document.write( ": \n" ); document.write( "Find the numbers 7 & 3 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this in the 1st statement \n" ); document.write( "\"Four times a first number decreased by a second number is 25\" \n" ); document.write( "4(7) - 3 = 25 \n" ); document.write( " \n" ); document.write( " |