document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032879>Question 1032879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 times the age of Kofi is 4 more than the age of Yaw. In three years, the sum of their ages will b 70yrs, find their present age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647465 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647465\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  3 times the age of Kofi is 4 more than the age of Yaw. In three years, the sum of their ages will b 70yrs, find their present age. <BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "3K = Y + 4<BR>\n" );
document.write( "K+3 + Y+3 = 70<BR>\n" );
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document.write( "Substitute for \"K\" and solve for \"Y\"::<BR>\n" );
document.write( "(Y+4)/3 + 3 + Y+3 = 70<BR>\n" );
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document.write( "Y+4 + 9 + 3Y + 9 = 210<BR>\n" );
document.write( "4Y + 22 = 210<BR>\n" );
document.write( "4Y = 188<BR>\n" );
document.write( "Y = 47 yrs<BR>\n" );
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document.write( "3K = Y+4<BR>\n" );
document.write( "K = (51/3) yrs  = 17 yrs (Kofi's age now)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "--------------- </SPAN>\n" );
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