document.write( "Question 1032872:  Heater A warms a room from 40 degrees to 70 degrees in 5 hours. Heater B can do this job in 7 hours. Heater A alone is started but breaks down in 2.5 hours. How long will it take heater B to finish the job. \r
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document.write( "* a chart would be especially helpful*  \n" );
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| Algebra.Com's Answer #647460 by josgarithmetic(39630)      You can put this solution on YOUR website! The exercise is intended as a uniform rates problem, each \"worker\" being a heater, working at its own rate. You can make a chart or table of rates.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "One job is \"warm the room air from 40 to 70 degree\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " HEATER RATE\r\n" ); document.write( "\r\n" ); document.write( "A 1/5\r\n" ); document.write( "\r\n" ); document.write( "B 1/7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another chart may be what you want, but the rest of the solution will be through equations only. The rule to use will be RT=J relating rate, time, job.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Once that is understood, solving for unknown time x is uncomplicated arithmetic. \n" ); document.write( " |