document.write( "Question 89056: factor completely:\r
\n" ); document.write( "\n" ); document.write( "y3-12y^2-36y \n" ); document.write( "
Algebra.Com's Answer #64746 by malakumar_kos@yahoo.com(315)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " factor completely:
\n" ); document.write( "y3-12y^2-36y y^3-12y^2-36y
\n" ); document.write( " = y(y^2-12y-36)
\n" ); document.write( " use the std formula y = -b+-sq rtb^2-4ac/2a where a = 1 b = -12 c = -36
\n" ); document.write( "
\n" ); document.write( " y = -(-12)+-sq rt(-12)^2-4.1(-36)/2.1\r
\n" ); document.write( "\n" ); document.write( " = 12+-sq rt144+144/2\r
\n" ); document.write( "\n" ); document.write( " = 12+-sq rt2.144/2
\n" ); document.write( " = 12+-12.sq rt2/2
\n" ); document.write( " = 12(1+-sq rt2)/2
\n" ); document.write( " = 6(1+-sq rt2)\r
\n" ); document.write( "\n" ); document.write( " therefore the value of y = 0 or value of y = 6(1+-sq rt2)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );