document.write( "Question 89064: solve:\r
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document.write( "5(x-2)^2=3 \n" );
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Algebra.Com's Answer #64743 by malakumar_kos@yahoo.com(315)![]() ![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( " solve:\r \n" ); document.write( "\n" ); document.write( "5(x-2)^2=3 consider 5(x-2)^2 = 3 \n" ); document.write( " 5(x^2-4x+4)-3 = 0 \n" ); document.write( " 5x^2-20x+20-3 = 0 \n" ); document.write( " 5x^2-20x+17 = 0\r \n" ); document.write( "\n" ); document.write( " use the standard formula x = -b+-sq rtb^2-4ac/2a\r \n" ); document.write( "\n" ); document.write( " where a = 5 b = -20 c = 17\r \n" ); document.write( "\n" ); document.write( " x = -(-20)+-sq rt(-20)^2-4(5)(17)/2.5 \n" ); document.write( " = 40+-sq rt(400-340)/10 \n" ); document.write( " = 40+-sq rt60/10 \n" ); document.write( " = 40+-2sq rt15/10 \n" ); document.write( " = 2(20+-sq rt15)/10 \n" ); document.write( " = (20+-sq rt15)/5 is the required solution \n" ); document.write( " |