document.write( "Question 89065: solve:\r
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document.write( "(x+2)^2=3 \n" );
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Algebra.Com's Answer #64741 by malakumar_kos@yahoo.com(315)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " solve:\r \n" ); document.write( "\n" ); document.write( "(x+2)^2=3\r \n" ); document.write( "\n" ); document.write( " consider (x+2)^2 = 3 \n" ); document.write( " x^2+4x+4-3= 0 \n" ); document.write( " x^2+4x+1 = 0\r \n" ); document.write( "\n" ); document.write( " use the formula x = -b +-sq rt b^2-4ac/2a where a = 1 b = 4 c = 1 \n" ); document.write( " x = -1+-sq rt 1^2-4.1.1/2.1 \n" ); document.write( " = -1+-sq rt 1-4/2 \n" ); document.write( " = -1+sq rt-3/2 since sq rt of negative number cannot be found we consider the solution as x = (-1+-sqrt-3)/2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |