document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032831>Question 1032831</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a truck travels 280 miles in the same time that it takes a car to travel 455 miles, if the truck is 25 miles per hour slower than the car find the rates  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647405 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In all these kinds of problems, we know the rate times time equals distance, or rt = d.<BR>\n" );
document.write( "Let us call the rate (or speed) of the truck, r.<BR>\n" );
document.write( "Then the rate of the car is r+25.<BR>\n" );
document.write( "The times each one travels are equal...so we can write (using t = d/r)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=280%2Fr+=+455%2F%28r%2B25%29 ALIGN=MIDDLE  ALT=\"280%2Fr+=+455%2F%28r%2B25%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now cross-multiply and solve for r...we get<BR>\n" );
document.write( "280r + 7000 = 455r<BR>\n" );
document.write( "Subtract 280r and get<BR>\n" );
document.write( "7000 = 175r<BR>\n" );
document.write( "r = 40 mph (truck) and<BR>\n" );
document.write( "r+25 = 65 mph (car) </SPAN>\n" );
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