document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12767>Question 12767</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help!  I need the answer to this problem:  A  soccer field is 75 yards shorter than 3 times its width.  Its perimeter is 370 yards.  Find its dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6474 by </B><A HREF=/tutors/aboutme.mpl?userid=vasu2qute><B>vasu2qute(17)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vasu2qute><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the width be x yards<BR>\n" );
document.write( "length=3x-75<BR>\n" );
document.write( "perimeter=2(length+width)=2(x+3x-75)=<BR>\n" );
document.write( "     2(4x-75) = 370<BR>\n" );
document.write( "       4x-75 =370/2<BR>\n" );
document.write( "       4x-75 =185<BR>\n" );
document.write( "        4x=185+75<BR>\n" );
document.write( "        4x=260<BR>\n" );
document.write( "         x=260/4=65<BR>\n" );
document.write( "therefore width=65yards , length= 3x-75=3x65-75=195-75=120yards </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );