document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032798>Question 1032798</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An arrow is fired into the air with an initial velocity of 64 feet per second. The height in<BR>\n" );
document.write( "feet of the arrow t seconds after it was shot into the air is given by the function<BR>\n" );
document.write( "h(x) = -16t2 + 64t. Find the maximum height of the arrow. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647384 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The form is a parabola opening downward. The maximum height is the vertex. \r<BR>\n" );
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document.write( "x=-b/2a = -64/(2*-16) = 2 so the maximum height occurs at t=2 sec. \r<BR>\n" );
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document.write( "h=-16(2^2)+64(2) = -64+128 = 64 ft max height.  </SPAN>\n" );
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