document.write( "Question 1032769: sarah has some dimes and quarters. If she has 29 coins worth a total of $4.40, how many of each type of coin does she have? \n" ); document.write( "

Algebra.Com's Answer #647357 by FrankM(1040) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let me offer the single variable method, which I think is the simplest to understand and use.
\n" ); document.write( "(Note - as I published, I saw Alan solved using 2 variables. You see we got the same answer. Use the method you find most comfortable to use. We proved there's often more than one way to approach a problem.)\r
\n" ); document.write( "\n" ); document.write( "Sarah has X dimes, they are worth 10X cents
\n" ); document.write( "She has (29-X) quarters, they are worth 25(29-X) cents\r
\n" ); document.write( "\n" ); document.write( "Her total value, is 440 cents, so \r
\n" ); document.write( "\n" ); document.write( "10X+25(29-X) = 440\r
\n" ); document.write( "\n" ); document.write( "10X + 725 - 25X = 440\r
\n" ); document.write( "\n" ); document.write( "-15X = -285\r
\n" ); document.write( "\n" ); document.write( "X = 19 (dimes) and 29-X=10 (quarters)\r
\n" ); document.write( "\n" ); document.write( "19 dimes are 190 cents
\n" ); document.write( "10 quarters are 250 cents\r
\n" ); document.write( "\n" ); document.write( "440 total. \r
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