document.write( "Question 89045: i. Explain how to apply elimination in solving a system of equations. \r
\n" ); document.write( "\n" ); document.write( "ii. Explain how to apply substitution in solving a system of equations. \r
\n" ); document.write( "\n" ); document.write( "iii. Demonstrate each technique in solving the system\r
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\n" ); document.write( "\n" ); document.write( "1. 3x + 9y = 12 \r
\n" ); document.write( "\n" ); document.write( "2. 5x - 4y = 3 \r
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Algebra.Com's Answer #64734 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( " i. Explain how to apply elimination in solving a system of equations.
\n" ); document.write( "ii. Explain how to apply substitution in solving a system of equations.
\n" ); document.write( "iii. Demonstrate each technique in solving the system \r
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\n" ); document.write( " To solve a system of linear equation by elimination process\r
\n" ); document.write( "\n" ); document.write( " 1)Bring the co-efficient of any one variable to the same .\r
\n" ); document.write( "\n" ); document.write( " 2) If the signs of both variable are same (having the same co-efficients)
\n" ); document.write( " then subtract the two eq's.\r
\n" ); document.write( "\n" ); document.write( " 3)If the signs are different then add the two eq'ns so that like terms get eliminated.
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\n" ); document.write( " 4)The value of one variable is calculated
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\n" ); document.write( " 5)By subtituting the value of known variable unknown variable can be \r
\n" ); document.write( "\n" ); document.write( " found.\r
\n" ); document.write( "\n" ); document.write( " solution: 1. 3x + 9y = 12 \r
\n" ); document.write( "\n" ); document.write( " 2. 5x - 4y = 3 \r
\n" ); document.write( "\n" ); document.write( " 1)L.C.M of 3,5 = 15 hence bring the co-efficient of x to 15\r
\n" ); document.write( "\n" ); document.write( " multiply eq'n(1) by 5 , and eq'n(2) by 3. The two eq'ns \r
\n" ); document.write( "\n" ); document.write( " reduces to 15x+45y = 60
\n" ); document.write( " 15x-12y = 9\r
\n" ); document.write( "\n" ); document.write( " 2) subtract the two eq'ns we get 57y = 51 , y = 51/57\r
\n" ); document.write( "\n" ); document.write( " 3) substituting the value of y in eq'n (1) we get
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\n" ); document.write( " 3x+9(51/57) = 12\r
\n" ); document.write( "\n" ); document.write( " 3x = 12- (459/57) = 684-459/57 = 225/57\r
\n" ); document.write( "\n" ); document.write( " x = 225/57*3 = 75/57 \r
\n" ); document.write( "\n" ); document.write( " solution is x = 75/57 and y = 51/57\r
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