document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032628>Question 1032628</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let z = 4(cos 3&#960;/2 + i sin 3&#960;/2) and w = 3(cos &#960;/6 + i sin &#960;/6). Write the rectangular form of z/w.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647303 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647303\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let z = 4(cos 3&#960;/2 + i sin 3&#960;/2) and w = 3(cos &#960;/6 + i sin &#960;/6). Write the rectangular form of z/w.<BR>\n" );
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document.write( "z = 4cis(3pi/2), w = 3cis(pi/6)<BR>\n" );
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document.write( "z/w = (4/3)cis(3pi/2 - pi/6) = (4/3)cis(4pi/3)<BR>\n" );
document.write( "z/w = (4/3)*cos(4pi/3) + (4i/3)*sin(4pi/3)<BR>\n" );
document.write( "z/w = (4/3)*(-1/2) + (4i/3)*(-sqrt(3)/2)<BR>\n" );
document.write( "z/w = -2/3 - i*2sqrt(3)/3<BR>\n" );
document.write( "= (2/3)*(-1 - sqrt(3)i)<BR>\n" );
document.write( "--> same answer as Stanbon </SPAN>\n" );
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