document.write( "Question 1032592: You currently drive 360 miles per week in a car that gets 20 miles per gallon of gas. You are
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document.write( "considering buying a new fuel-efficient car for $12,000 (after trade-in on your current car) that gets
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document.write( "60 miles per gallon. Insurance premiums for the new and old car are $900 and $600 per year,
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document.write( "respectively. You anticipate spending $1400 per year on repairs for the old car and having no
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document.write( "repairs on the new car. Assume gas costs $3.50 per gallon. Over a five-year period, is it less
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document.write( "expensive to keep your old car or buy the new car? By how much?\r
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document.write( "A) the new car is $4420 less expensive
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document.write( "B) the new car is $3120 less expensive
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document.write( "C) the old car is $4420 less expensive
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document.write( "D) the old car is $3120 less expensive\r
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Algebra.Com's Answer #647275 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "You currently drive 360 miles per week \n" ); document.write( "in a car that gets 20 miles per gallon of gas.\r \n" ); document.write( "\n" ); document.write( "Total cost on the old car \n" ); document.write( "((360 miles per week *52 * 5years)/20) *3.50 $ + (600*5)+1400*5) \n" ); document.write( "=$26380\r \n" ); document.write( "\n" ); document.write( "Total cost on the new car \r \n" ); document.write( "\n" ); document.write( "12000 + ((360*52*5)/60))*3.50 *(900*5) \r \n" ); document.write( "\n" ); document.write( "=$21960 \n" ); document.write( " A) the new car is $4420 less expensive \n" ); document.write( " \n" ); document.write( " |