document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032561>Question 1032561</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem:<BR>\n" );
document.write( "A right circular cone is inscribed inside a hemisphere so that its base is the same as the hemisphere. If the radius of the hemisphere is increasing at a rate of 1 cm/sec, find the rate at which the total volume of the cone is increasing when the radius of the base is 4cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647272 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647272\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A right circular cone is inscribed inside a hemisphere so that its base is the same as the hemisphere. If the radius of the hemisphere is increasing at a rate of 1 cm/sec, find the rate at which the total volume of the cone is increasing when the radius of the base is 4cm<BR>\n" );
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document.write( "The height of the cone = radius.<BR>\n" );
document.write( "--> Vol = pi*r^2*r/3 = pi*r^3/3<BR>\n" );
document.write( "dV/dt = pi*r^2*dr/dt<BR>\n" );
document.write( "At r = 4, dV/dt = 16pi cc/sec\r<BR>\n" );
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