document.write( "Question 1032573: The sum of three integers is
\n" ); document.write( "270. The sum of the first and second integers exceeds the third by
\n" ); document.write( "98.
\n" ); document.write( "The third integer is
\n" ); document.write( "47 less than the first.
\n" ); document.write( "Find the three integers
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Algebra.Com's Answer #647235 by fractalier(6550)\"\" \"About 
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Call the three integers x, y, and z. Then we write
\n" ); document.write( "x + y + z = 270
\n" ); document.write( "x + y = z + 98
\n" ); document.write( "z = x - 47
\n" ); document.write( "Now substitute the second into the first and get
\n" ); document.write( "z+98 + z = 270
\n" ); document.write( "2z + 98 = 270
\n" ); document.write( "2z = 172
\n" ); document.write( "z = 86
\n" ); document.write( "Then
\n" ); document.write( "86 = x - 47 and
\n" ); document.write( "x = 133
\n" ); document.write( "Plugging x and z in to the first gives us y...
\n" ); document.write( "133 + y + 86 = 270
\n" ); document.write( "219 + y = 270
\n" ); document.write( "y = 51
\n" ); document.write( "Your numbers are 133, 51 and 86.
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