document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032567>Question 1032567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a tree needs to be staked down prior to a storm. if the ropes can be tied on the tree trunk 10 feet above the ground and the staked rope should make a 30 degrees angle with the ground, how far from the base of the tree should the ropes be staked?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647226 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you draw yourself the diagram you will find that the triangle you draw is a 30-60-90 right triangle...<BR>\n" );
document.write( "The sides are always in the ratio of 1-2-sqrt(3)...<BR>\n" );
document.write( "The side you want is the sqrt(3) side...its length is<BR>\n" );
document.write( "10*sqrt(3) = 17.32 feet </SPAN>\n" );
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