document.write( "Question 1032445: Use the definite integral to find the area between the​ x-axis and​ f(x) over the indicated interval. Check first to see if the graph crosses the​ x-axis in the given interval. \r
\n" ); document.write( "\n" ); document.write( "f(x)=1-x^2; [0,2] \r
\n" ); document.write( "\n" ); document.write( "Question: The area between the x-axis and f(x) is ???
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Algebra.Com's Answer #647207 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\"A=int%28%28f%28x%29%29%2Cdx%2C0%2C1%29%2Bint%28%28-f%28x%29%29%2Cdx%2C1%2C2%29\"
\n" ); document.write( "\"A=int%28%281-x%5E2%29%2Cdx%2C0%2C1%29%2Bint%28%28x%5E2-1%29%2Cdx%2C1%2C2%29\"
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\n" ); document.write( "\n" ); document.write( "\"A%5B1%5D=x-x%5E3%2F3%2BC\"
\n" ); document.write( "\"A%5B1%5D=%281-0%29-%281%5E3-0%5E3%29%2F3\"
\n" ); document.write( "\"A%5B1%5D=1-1%2F3\"
\n" ); document.write( "\"A%5B1%5D=2%2F3\"
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\n" ); document.write( "\"A%5B2%5D=x%5E3%2F3-x%2BC\"
\n" ); document.write( "\"A%5B2%5D=%282%5E3-1%5E3%29%2F3-%282-1%29\"
\n" ); document.write( "\"A%5B2%5D=%288-1%29%2F3-1\"
\n" ); document.write( "\"A%5B2%5D=7%2F3-3%2F3\"
\n" ); document.write( "\"A%5B2%5D=4%2F3\"
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\n" ); document.write( "\"A=A%5B1%5D%2BA%5B2%5D\"
\n" ); document.write( "\"A=2%2F3%2B4%2F3\"
\n" ); document.write( "\"A=2\"
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\n" ); document.write( " This previous method assumes the area below the x-axis is treated as positive also.
\n" ); document.write( "If you treat this as negative then the sum would change to,
\n" ); document.write( "\"A=A%5B1%5D-A%5B2%5D\"
\n" ); document.write( "\"A=2%2F3-4%2F3\"
\n" ); document.write( "\"A=-2%2F3\"
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