document.write( "Question 1032530: Pls help me solve this. this is the last equation for my homework.\r
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document.write( "Robert has 35 coins consisting dimes and quarters. If the total value is $5.90, how many of each kind of coin are there? \n" );
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Algebra.Com's Answer #647203 by ikleyn(52790)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Pls help me solve this. this is the last equation for my homework.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Robert has 35 coins consisting dimes and quarters. If the total value is $5.90, how many of each kind of coin are there? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or this another solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let d be the number of dimes.\r\n" ); document.write( "Then the number of quarters is 35-d.\r\n" ); document.write( "\r\n" ); document.write( "The dimes contribute 10*d cents to the total. \r\n" ); document.write( "The quarters contribute 25*(35-d) cents to the total.\r\n" ); document.write( "\r\n" ); document.write( "As a result, the total is 10*d + 25*(35-d).\r\n" ); document.write( "Since the total is 590 cents, it gives you an equation\r\n" ); document.write( "\r\n" ); document.write( "10*d + 25*(35-d) = 590.\r\n" ); document.write( "\r\n" ); document.write( "Simplify and solve it for d:\r\n" ); document.write( "\r\n" ); document.write( "10d + 875 - 25d = 590,\r\n" ); document.write( "\r\n" ); document.write( "10d - 25d = 590 -875,\r\n" ); document.write( "\r\n" ); document.write( "-15d = -285,\r\n" ); document.write( "\r\n" ); document.write( "d = \n" ); document.write( " \n" ); document.write( " |