document.write( "Question 12730: please help me. solve the following.
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document.write( "2m - 5
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document.write( "------- = 3
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document.write( " 9\r
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document.write( "First thing you do is multiply both sides by 9.
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document.write( "(2m-5)(9)/9 = 3(9)\r
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document.write( "The nines should cancel\r
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document.write( "2m - 5 = 3 x 9\r
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document.write( "We know that 3 x 9 = 27\r
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document.write( "2m -5 = 27\r
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document.write( "Then add 5 to both sides\r
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document.write( "2m - 5 + 5 = 27 + 5\r
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document.write( "The 5's cancel each other\r
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document.write( "2m = 32 \r
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document.write( "divide both sides by 2\r
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document.write( "2m/2 = 32/2\r
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document.write( "m = 16 \n" );
document.write( "
Algebra.Com's Answer #6472 by drpotillor(1)![]() ![]() ![]() You can put this solution on YOUR website! please help me. solve the following. \n" ); document.write( "2m - 5 \n" ); document.write( "------- = 3 \n" ); document.write( " 9\r \n" ); document.write( "\n" ); document.write( "First thing you do is multiply both sides by 9. \n" ); document.write( "(2m-5)(9)/9 = 3(9)\r \n" ); document.write( "\n" ); document.write( "The nines should cancel\r \n" ); document.write( "\n" ); document.write( "2m - 5 = 3 x 9\r \n" ); document.write( "\n" ); document.write( "We know that 3 x 9 = 27\r \n" ); document.write( "\n" ); document.write( "2m -5 = 27\r \n" ); document.write( "\n" ); document.write( "Then add 5 to both sides\r \n" ); document.write( "\n" ); document.write( "2m - 5 + 5 = 27 + 5\r \n" ); document.write( "\n" ); document.write( "The 5's cancel each other\r \n" ); document.write( "\n" ); document.write( "2m = 32 \r \n" ); document.write( "\n" ); document.write( "divide both sides by 2\r \n" ); document.write( "\n" ); document.write( "2m/2 = 32/2\r \n" ); document.write( "\n" ); document.write( "m = 16 \n" ); document.write( " |