document.write( "Question 1032065: A plane can fly 510 miles in the same time as it takes a car to go 120 miles. If the car travels 130 mph slower than the plane, find the speed of the plane.
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #647199 by LinnW(1048) $\"\"$ $\"About$

You can put this solution on YOUR website!
Set c = speed of car in mph
\n" ); document.write( "p = speed of plane in mph
\n" ); document.write( "t = time of travel
\n" ); document.write( "c = p - 130
\n" ); document.write( "c*t = 120
\n" ); document.write( "p*t = 510
\n" ); document.write( "substitute ( p - 130 ) for c in c*t
\n" ); document.write( "( p - 130 )t = 120
\n" ); document.write( "Solve for t by dividing by ( p - 130 )
\n" ); document.write( "t = 120/( p - 130 )
\n" ); document.write( "Solve for t in p*t = 510 by dividing by p
\n" ); document.write( "t = 510/p
\n" ); document.write( " $\"120%2F%28+p+-+130+%29+=+510%2Fp\"$
\n" ); document.write( "Do cross products
\n" ); document.write( "120p = 510(p - 130)
\n" ); document.write( "120p = 510p - 510*130
\n" ); document.write( "divide each side by 10
\n" ); document.write( "12p = 51p - 510*13
\n" ); document.write( "-39p = -6630
\n" ); document.write( "divide each side by -39
\n" ); document.write( "p = 170 \n" ); document.write( "

\n" );