document.write( "Question 1032471: how many 20% acid solution should be mixed with 6 oz of 30% acid solution to produce a mixture that is 28% acid? \r
\n" ); document.write( "\n" ); document.write( "could u make a chart because I like visuals. I want to be able to use the same concept with other similar mixture problems. Thanks. \n" ); document.write( "
Algebra.Com's Answer #647132 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
how many 20% acid solution should be mixed with 6 oz of 30% acid solution to produce a mixture that is 28% acid?
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\n" ); document.write( "Sketch 3 jugs
\n" ); document.write( "Start jug has x oz of 20% solution
\n" ); document.write( "Second jug as 6 oz of 30% solution
\n" ); document.write( "Result jug has (x+6)oz of 28% solution
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\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.20x + 0.30*6 = 0.28(x+6)
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\n" ); document.write( "20x + 30*6 = 28x + 28*6
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\n" ); document.write( "8x = 2*6
\n" ); document.write( "x = 12/8 = 3/2 oz (amt. of 20% to add)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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