document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032330>Question 1032330</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Q: Lionel invested an amount of 20,000$ partly at the rate of 5% and partly at the rate of 8% interest per anum.If the total amount of interest at the end of one year is 1,420$,how much was invested at 5% ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647118 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647118\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount invested at 5%,y=amount invested at 8%. We know that:<BR>\n" );
document.write( "x+y=20000<BR>\n" );
document.write( ".05x+.08y=1420<BR>\n" );
document.write( "Multiplying through we get:<BR>\n" );
document.write( ".08x+.08y=.08(20000)=1600<BR>\n" );
document.write( ".05x+.08y=1420\r<BR>\n" );
document.write( "\n" );
document.write( ".03x=1600-1420=180<BR>\n" );
document.write( "x=18/.03=6000<BR>\n" );
document.write( "y=140000!!!!!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );