document.write( "Question 89028: WHat is the perimeter of a rectangle with a length of 23 ft. and a area of 322 sq. ft????? \n" ); document.write( "
Algebra.Com's Answer #64711 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " WHat is the perimeter of a rectangle with a length of 23 ft. and a area of 322 sq. ft?????\r
\n" ); document.write( "\n" ); document.write( " Let the breadth of the rectangle be = b ft\r
\n" ); document.write( "\n" ); document.write( " the length of the rectangle = l = 23 ft\r
\n" ); document.write( "\n" ); document.write( " Area of the rectangle is = A = 322 sq ft\r
\n" ); document.write( "\n" ); document.write( " Perimeter of the rectangle = P = ?\r
\n" ); document.write( "\n" ); document.write( " A = l*b
\n" ); document.write( " 322 = 23*b or b = 322/23 = 14 ft\r
\n" ); document.write( "\n" ); document.write( " P = 2(l+b) = 2(23+14) = 2(37) = 74 ft.\r
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