document.write( "Question 1032419: The length of a rectangle is four times its width. If the perimeter of the rectangle is 50 ft, find its area \n" ); document.write( "

Algebra.Com's Answer #647077 by josgarithmetic(39618) $\"\"$ $\"About$

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w width, L length;\r
\n" ); document.write( "\n" ); document.write( " $\"L=4w\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"2w%2B2L=50\"$
\n" ); document.write( " $\"2w%2B2%284w%29=50\"$
\n" ); document.write( " $\"10w=50\"$
\n" ); document.write( " $\"w=5\"$ -----------meaning length is $\"L=20\"$ .\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Area is $\"w%2AL\"$ . \n" ); document.write( "

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