document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032312>Question 1032312</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 15-person road crew is scheduled to finish repairing a highway in 12 days. On the morning of the fifth day, several new workers join the crew and, together, they complete the remaining repairs in 6 days. How many new workers joined the crew? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #647031 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=647031\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There is a requirement of 15*12 = 180 person-days to finish repairing the highway.  Since it has been 4 days that the crew has been working, 4*15 = 60 person-days have already been accomplished.  The remaining work is done by 15+x persons in 6 days.  Hence, \r<BR>\n" );
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document.write( "60 + 6(15+x) = 180\r<BR>\n" );
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document.write( "==> 6(15+x) = 120<BR>\n" );
document.write( "==> 15+x = 20 <BR>\n" );
document.write( "==> x = 5.<BR>\n" );
document.write( "Therefore five new workers joined the crew. </SPAN>\n" );
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