document.write( "Question 1032364: With reference to the fact that the functions log2 x and 2^x undo each other, explain each of the
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\n" ); document.write( "(a) log2 0 is undefined.
\n" ); document.write( "(b) log2 x is negative when x is between 0 and 1.
\n" ); document.write( "(c) log2 500 is between 8 and 9.
\n" ); document.write( "(d) An x can be found so that log2(x) is greater than 1, 000, 000.\r
\n" ); document.write( "\n" ); document.write( "in all the log2 above 2 is the power of the log . I couldn't find a way to put the correct form in here.
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Algebra.Com's Answer #647015 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
(a) \"log%282%2C0%29\" is undefined because there is NO real number x such that \"2%5Ex+=+0\". \r
\n" ); document.write( "\n" ); document.write( "(b) \"+log%282%2C+x%29\" is negative when x is between 0 and 1 because, if you will notice the graph of \"y=2%5Ex\", for \"0+%3C+y=2%5Ex+%3C1\", the corresponding set of pullback x-values is exactly the interval (\"-infinity\", 0).
\n" ); document.write( "\"graph%28+300%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+2%5Ex%29\"\r
\n" ); document.write( "\n" ); document.write( "(c) This is easy, because \"2%5E8+=256+%3C+500+%3C+2%5E9=512\".\r
\n" ); document.write( "\n" ); document.write( "(d) An x can be found so that \"log%282%2Cx%29\" is greater than 1,000,000. Indeed, \"2%5E20+\" = 1,048,576 > 1,000,000.\r
\n" ); document.write( "\n" ); document.write( "You have to remember that logarithm is just a fancy way of writing an exponent satisfying a base condition.
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