document.write( "Question 89012: write he equation of the line with slope -1/2 and y-intercept (0,3). Then graph the line. \n" ); document.write( "
Algebra.Com's Answer #64700 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"-1%2F2\" which goes through the point (\"0\",\"3\"), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope, and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=%28-1%2F2%29%28x-0%29\" Plug in \"m=-1%2F2\", \"x%5B1%5D=0\", and \"y%5B1%5D=3\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=%28-1%2F2%29x-%28-1%2F2%29%280%29%29\" Distribute \"-1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=%28-1%2F2%29x%2B%281%2F2%29%280%29%29\" Multiply the negatives\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=%28-1%2F2%29x%2B0\" Multiply \"1%2F2\" and \"0\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-1%2F2%29x%2B0%2B3\"Add \"3\" to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-1%2F2%29x%2B3\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"-1%2F2\" which goes through the point (\"0\",\"3\") is:\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-1%2F2%29x%2B3\" which is now in \"y=mx%2Bb\" form where the slope is \"m=-1%2F2\" and the y-intercept is \"b=3\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%28-1%2F2%29x%2B3\" and plot the point (\"0\",\"3\"), we get (note: if you need help with graphing, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%28-1%2F2%29x%2B3\" through the point (\"0\",\"3\")\r
\n" ); document.write( "\n" ); document.write( "and we can see that the point lies on the line. Since we know the equation has a slope of \"-1%2F2\" and goes through the point (\"0\",\"3\"), this verifies our answer.
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