document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032258>Question 1032258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ladder is leaning against a building so that the distance from the ground to the top of the ladder is 3 feet less than the length of the ladder. Find the length of the ladder if the distance from the bottom of the ladder to the building is sqrt(39) feet.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646997 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A ladder is leaning against a building so that the distance from the ground to the top of the ladder is 3 feet less than the length of the ladder. Find the length of the ladder if the distance from the bottom of the ladder to the building is sqrt(39) feet. <BR>\n" );
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document.write( "Sketch the picture.<BR>\n" );
document.write( "You have a right triangle with height = L-3 ft<BR>\n" );
document.write( "and base = sqrt(39)<BR>\n" );
document.write( "and hypotenuse = L<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "L^2 = (sqrt(39))^2 + L^2 - 6L + 9<BR>\n" );
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document.write( "6L = 39+9<BR>\n" );
document.write( "L = 8 ft (length of the ladder)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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