document.write( "Question 89000: Solve each system by using both the substitution and addition methods:\r
\n" ); document.write( "\n" ); document.write( "A. 4x-y=6
\n" ); document.write( " x-y=0\r
\n" ); document.write( "\n" ); document.write( "B. 5x+2y=1
\n" ); document.write( " x-3y=7
\n" ); document.write( "

Algebra.Com's Answer #64696 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
A.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Here is the elimination method:
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"4%2Ax-1%2Ay=6\"
\n" ); document.write( " \"1%2Ax-1%2Ay=0\"
\n" ); document.write( "
\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
\n" ); document.write( "
\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
\n" ); document.write( "
\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 4 and 1 to some equal number, we could try to get them to the LCM.
\n" ); document.write( "
\n" ); document.write( " Since the LCM of 4 and 1 is 4, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -4 like this:
\n" ); document.write( "
\n" ); document.write( " \"1%2A%284%2Ax-1%2Ay%29=%286%29%2A1\" Multiply the top equation (both sides) by 1
\n" ); document.write( " \"-4%2A%281%2Ax-1%2Ay%29=%280%29%2A-4\" Multiply the bottom equation (both sides) by -4
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"4%2Ax-1%2Ay=6\"
\n" ); document.write( " \"-4%2Ax%2B4%2Ay=0\"
\n" ); document.write( "
\n" ); document.write( " Notice how 4 and -4 add to zero (ie \"4%2B-4=0\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%284%2Ax-4%2Ax%29-1%2Ay%2B4%2Ay%29=6%2B0\"
\n" ); document.write( "
\n" ); document.write( " \"%284-4%29%2Ax-1%2B4%29y=6%2B0\"
\n" ); document.write( "
\n" ); document.write( " \"cross%284%2B-4%29%2Ax%2B%28-1%2B4%29%2Ay=6%2B0\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after adding and canceling out the x terms we're left with:
\n" ); document.write( "
\n" ); document.write( " \"3%2Ay=6\"
\n" ); document.write( "
\n" ); document.write( " \"y=6%2F3\" Divide both sides by \"3\" to solve for y
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=2\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now plug this answer into the top equation \"4%2Ax-1%2Ay=6\" to solve for x
\n" ); document.write( "
\n" ); document.write( " \"4%2Ax-1%282%29=6\" Plug in \"y=2\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"4%2Ax-2=6\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"4%2Ax=6%2B2\" Subtract \"-2\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"4%2Ax=8\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F4%29%284%29%29%2Ax=%288%29%281%2F4%29\" Multiply both sides by \"1%2F4\". This will cancel out \"4\" on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=2\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our answer is
\n" ); document.write( "
\n" ); document.write( " \"x=2\", \"y=2\"
\n" ); document.write( "
\n" ); document.write( " which also looks like
\n" ); document.write( "
\n" ); document.write( " (\"2\", \"2\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"4%2Ax-1%2Ay=6\"
\n" ); document.write( " \"1%2Ax-1%2Ay=0\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"4%2Ax-1%2Ay=6\" (red) \"1%2Ax-1%2Ay=0\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"2\",\"2\"). This verifies our answer.

\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "Here is the substitution method:
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a linear system of equations by subsitution

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"4%2Ax-1%2Ay=6\"
\n" ); document.write( " \"1%2Ax-1%2Ay=0\"
\n" ); document.write( "
\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
\n" ); document.write( "
\n" ); document.write( " Solve for y for the first equation
\n" ); document.write( "
\n" ); document.write( " \"-1%2Ay=6-4%2Ax\"Subtract \"4%2Ax\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"y=%286-4%2Ax%29%2F-1\" Divide both sides by -1.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Which breaks down and reduces to
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-6%2B4%2Ax\" Now we've fully isolated y
\n" ); document.write( "
\n" ); document.write( " Since y equals \"-6%2B4%2Ax\" we can substitute the expression \"-6%2B4%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B-1%2Ahighlight%28%28-6%2B4%2Ax%29%29=0\" Replace y with \"-6%2B4%2Ax\". Since this eliminates y, we can now solve for x.
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax-1%2A%28-6%29-1%284%29x=0\" Distribute -1 to \"-6%2B4%2Ax\"
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B6-4%2Ax=0\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B6-4%2Ax=0\" Reduce any fractions
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax-4%2Ax=0-6\" Subtract \"6\" from both sides
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax-4%2Ax=-6\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"-3%2Ax=-6\" Now combine the terms on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F-3%29%28-3%2F1%29%29x=%28-6%2F1%29%281%2F-3%29\" Multiply both sides by \"1%2F-3\". This will cancel out \"-3%2F1\" and isolate x
\n" ); document.write( "
\n" ); document.write( " So when we multiply \"-6%2F1\" and \"1%2F-3\" (and simplify) we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=2\" <---------------------------------One answer
\n" ); document.write( "
\n" ); document.write( " Now that we know that \"x=2\", lets substitute that in for x to solve for y
\n" ); document.write( "
\n" ); document.write( " \"1%282%29-1%2Ay=0\" Plug in \"x=2\" into the 2nd equation
\n" ); document.write( "
\n" ); document.write( " \"2-1%2Ay=0\" Multiply
\n" ); document.write( "
\n" ); document.write( " \"-1%2Ay=0-2\"Subtract \"2\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"-1%2Ay=-2\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F-1%29%28-1%29%29%2Ay=%28-2%2F1%29%281%2F-1%29\" Multiply both sides by \"1%2F-1\". This will cancel out -1 on the left side.
\n" ); document.write( "
\n" ); document.write( " \"y=-2%2F-1\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=2\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So this is the other answer
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=2\"<---------------------------------Other answer
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our solution is
\n" ); document.write( "
\n" ); document.write( " \"x=2\" and \"y=2\"
\n" ); document.write( "
\n" ); document.write( " which can also look like
\n" ); document.write( "
\n" ); document.write( " (\"2\",\"2\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"4%2Ax-1%2Ay=6\"
\n" ); document.write( " \"1%2Ax-1%2Ay=0\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"4%2Ax-1%2Ay=6\" (red) and \"1%2Ax-1%2Ay=0\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"2\",\"2\"). This verifies our answer.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " -----------------------------------------------------------------------------------------------
\n" ); document.write( " Check:
\n" ); document.write( "
\n" ); document.write( " Plug in (\"2\",\"2\") into the system of equations
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Let \"x=2\" and \"y=2\". Now plug those values into the equation \"4%2Ax-1%2Ay=6\"
\n" ); document.write( "
\n" ); document.write( " \"4%2A%282%29-1%2A%282%29=6\" Plug in \"x=2\" and \"y=2\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"8-2=6\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"6=6\" Add
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"6=6\" Reduce. Since this equation is true the solution works.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the solution (\"2\",\"2\") satisfies \"4%2Ax-1%2Ay=6\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Let \"x=2\" and \"y=2\". Now plug those values into the equation \"1%2Ax-1%2Ay=0\"
\n" ); document.write( "
\n" ); document.write( " \"1%2A%282%29-1%2A%282%29=0\" Plug in \"x=2\" and \"y=2\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"2-2=0\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"0=0\" Add
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"0=0\" Reduce. Since this equation is true the solution works.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the solution (\"2\",\"2\") satisfies \"1%2Ax-1%2Ay=0\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the solution (\"2\",\"2\") satisfies the system of equations
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"4%2Ax-1%2Ay=6\"
\n" ); document.write( " \"1%2Ax-1%2Ay=0\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " this verifies our answer.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "===============================================\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "B.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Here is the elimination method:
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax%2B2%2Ay=1\"
\n" ); document.write( " \"1%2Ax-3%2Ay=7\"
\n" ); document.write( "
\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
\n" ); document.write( "
\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
\n" ); document.write( "
\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 5 and 1 to some equal number, we could try to get them to the LCM.
\n" ); document.write( "
\n" ); document.write( " Since the LCM of 5 and 1 is 5, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -5 like this:
\n" ); document.write( "
\n" ); document.write( " \"1%2A%285%2Ax%2B2%2Ay%29=%281%29%2A1\" Multiply the top equation (both sides) by 1
\n" ); document.write( " \"-5%2A%281%2Ax-3%2Ay%29=%287%29%2A-5\" Multiply the bottom equation (both sides) by -5
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"5%2Ax%2B2%2Ay=1\"
\n" ); document.write( " \"-5%2Ax%2B15%2Ay=-35\"
\n" ); document.write( "
\n" ); document.write( " Notice how 5 and -5 add to zero (ie \"5%2B-5=0\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%285%2Ax-5%2Ax%29%2B%282%2Ay%2B15%2Ay%29=1-35\"
\n" ); document.write( "
\n" ); document.write( " \"%285-5%29%2Ax%2B%282%2B15%29y=1-35\"
\n" ); document.write( "
\n" ); document.write( " \"cross%285%2B-5%29%2Ax%2B%282%2B15%29%2Ay=1-35\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after adding and canceling out the x terms we're left with:
\n" ); document.write( "
\n" ); document.write( " \"17%2Ay=-34\"
\n" ); document.write( "
\n" ); document.write( " \"y=-34%2F17\" Divide both sides by \"17\" to solve for y
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-2\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now plug this answer into the top equation \"5%2Ax%2B2%2Ay=1\" to solve for x
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax%2B2%28-2%29=1\" Plug in \"y=-2\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax-4=1\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax=1%2B4\" Subtract \"-4\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax=5\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F5%29%285%29%29%2Ax=%285%29%281%2F5%29\" Multiply both sides by \"1%2F5\". This will cancel out \"5\" on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=1\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our answer is
\n" ); document.write( "
\n" ); document.write( " \"x=1\", \"y=-2\"
\n" ); document.write( "
\n" ); document.write( " which also looks like
\n" ); document.write( "
\n" ); document.write( " (\"1\", \"-2\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax%2B2%2Ay=1\"
\n" ); document.write( " \"1%2Ax-3%2Ay=7\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"5%2Ax%2B2%2Ay=1\" (red) \"1%2Ax-3%2Ay=7\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"1\",\"-2\"). This verifies our answer.

\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "Here is the substitution method:
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a linear system of equations by subsitution

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax%2B2%2Ay=1\"
\n" ); document.write( " \"1%2Ax-3%2Ay=7\"
\n" ); document.write( "
\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
\n" ); document.write( "
\n" ); document.write( " Solve for y for the first equation
\n" ); document.write( "
\n" ); document.write( " \"2%2Ay=1-5%2Ax\"Subtract \"5%2Ax\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"y=%281-5%2Ax%29%2F2\" Divide both sides by 2.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Which breaks down and reduces to
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=1%2F2-%285%2F2%29%2Ax\" Now we've fully isolated y
\n" ); document.write( "
\n" ); document.write( " Since y equals \"1%2F2-%285%2F2%29%2Ax\" we can substitute the expression \"1%2F2-%285%2F2%29%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B-3%2Ahighlight%28%281%2F2-%285%2F2%29%2Ax%29%29=7\" Replace y with \"1%2F2-%285%2F2%29%2Ax\". Since this eliminates y, we can now solve for x.
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax-3%2A%281%2F2%29-3%28-5%2F2%29x=7\" Distribute -3 to \"1%2F2-%285%2F2%29%2Ax\"
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax-3%2F2%2B%2815%2F2%29%2Ax=7\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax-3%2F2%2B%2815%2F2%29%2Ax=7\" Reduce any fractions
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B%2815%2F2%29%2Ax=7%2B3%2F2\"Add \"3%2F2\" to both sides
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B%2815%2F2%29%2Ax=14%2F2%2B3%2F2\" Make 7 into a fraction with a denominator of 2
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B%2815%2F2%29%2Ax=17%2F2\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"%282%2F2%29%2Ax%2B%2815%2F2%29x=17%2F2\" Make 1 into a fraction with a denominator of 2
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\n" ); document.write( " \"%2817%2F2%29%2Ax=17%2F2\" Now combine the terms on the left side.
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\n" ); document.write( " \"cross%28%282%2F17%29%2817%2F2%29%29x=%2817%2F2%29%282%2F17%29\" Multiply both sides by \"2%2F17\". This will cancel out \"17%2F2\" and isolate x
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\n" ); document.write( " So when we multiply \"17%2F2\" and \"2%2F17\" (and simplify) we get
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\n" ); document.write( " \"x=1\" <---------------------------------One answer
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\n" ); document.write( " Now that we know that \"x=1\", lets substitute that in for x to solve for y
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\n" ); document.write( " \"1%281%29-3%2Ay=7\" Plug in \"x=1\" into the 2nd equation
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\n" ); document.write( " \"1-3%2Ay=7\" Multiply
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\n" ); document.write( " \"-3%2Ay=7-1\"Subtract \"1\" from both sides
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\n" ); document.write( " \"-3%2Ay=6\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F-3%29%28-3%29%29%2Ay=%286%2F1%29%281%2F-3%29\" Multiply both sides by \"1%2F-3\". This will cancel out -3 on the left side.
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\n" ); document.write( " \"y=6%2F-3\" Multiply the terms on the right side
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\n" ); document.write( " \"y=-2\" Reduce
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\n" ); document.write( " So this is the other answer
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\n" ); document.write( " \"y=-2\"<---------------------------------Other answer
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\n" ); document.write( "
\n" ); document.write( " So our solution is
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\n" ); document.write( " \"x=1\" and \"y=-2\"
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\n" ); document.write( " which can also look like
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\n" ); document.write( " (\"1\",\"-2\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"5%2Ax%2B2%2Ay=1\"
\n" ); document.write( " \"1%2Ax-3%2Ay=7\"
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\n" ); document.write( " we get
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\n" ); document.write( "
\n" ); document.write( " graph of \"5%2Ax%2B2%2Ay=1\" (red) and \"1%2Ax-3%2Ay=7\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
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\n" ); document.write( " and we can see that the two equations intersect at (\"1\",\"-2\"). This verifies our answer.
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\n" ); document.write( " Check:
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\n" ); document.write( " Plug in (\"1\",\"-2\") into the system of equations
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\n" ); document.write( " Let \"x=1\" and \"y=-2\". Now plug those values into the equation \"5%2Ax%2B2%2Ay=1\"
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\n" ); document.write( " \"5%2A%281%29%2B2%2A%28-2%29=1\" Plug in \"x=1\" and \"y=-2\"
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\n" ); document.write( " \"5-4=1\" Multiply
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\n" ); document.write( " \"1=1\" Add
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\n" ); document.write( " \"1=1\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( "
\n" ); document.write( " So the solution (\"1\",\"-2\") satisfies \"5%2Ax%2B2%2Ay=1\"
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\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Let \"x=1\" and \"y=-2\". Now plug those values into the equation \"1%2Ax-3%2Ay=7\"
\n" ); document.write( "
\n" ); document.write( " \"1%2A%281%29-3%2A%28-2%29=7\" Plug in \"x=1\" and \"y=-2\"
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\n" ); document.write( "
\n" ); document.write( " \"1%2B6=7\" Multiply
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\n" ); document.write( " \"7=7\" Add
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\n" ); document.write( "
\n" ); document.write( " \"7=7\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( "
\n" ); document.write( " So the solution (\"1\",\"-2\") satisfies \"1%2Ax-3%2Ay=7\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the solution (\"1\",\"-2\") satisfies the system of equations
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"5%2Ax%2B2%2Ay=1\"
\n" ); document.write( " \"1%2Ax-3%2Ay=7\"
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\n" ); document.write( "
\n" ); document.write( " this verifies our answer.
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