document.write( "Question 1032302: 4x^2+3y^2=4
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Algebra.Com's Answer #646959 by ikleyn(52800)\"\" \"About 
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document.write( "4x^2 + 3y^2 =  4,    (1)\r\n" );
document.write( "2x   - 2y^2 = -3.    (2)\r\n" );
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document.write( "From (2), express 2x = \"-3+%2B+2y%5E2\". Now, substitute it into (1) by noting that \"4x%5E2\" = \"%282x%29%5E2\". You will get a single equation for \"y%5E2\":\r\n" );
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document.write( "\"%28-3%2B2y%5E2%29%5E2\" + \"3y%5E2\" = 4.\r\n" );
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document.write( "Open parentheses, collect the like terms and introduce the new variable z = \"y%5E2\".\r\n" );
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document.write( "Solve the obtained quadratic equation for z.\r\n" );
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document.write( "Then find \"y\" from z = \"y%5E2\".\r\n" );
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document.write( "Then find \"x\" from (2).\r\n" );
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