document.write( "Question 1032321: For which value of x does (square root of x-5)+2=6\r
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Algebra.Com's Answer #646956 by ikleyn(52781)\"\" \"About 
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document.write( "\"sqrt%28x-5%29+%2B+2\" = \"6\"  ---> (add - 2 to both sides, and get)\r\n" );
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document.write( "\"sqrt%28x-5%29\" = \"4\".         ( square both sides and get)\r\n" );
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document.write( "x -5 = 16.\r\n" );
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document.write( "x = 16 + 5 = 21.\r\n" );
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document.write( "Check it!\r\n" );
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