document.write( "Question 1032327: A chemist has two solutions of hydrochloric acid in stock: a 50% solution and an 80% solution. How much of each should be used to obtain 100 milliliters of a 68% solution? \n" ); document.write( "
Algebra.Com's Answer #646953 by ikleyn(52786)![]() ![]() You can put this solution on YOUR website! A chemist has two solutions of hydrochloric acid in stock: a 50% solution and an 80% solution. How much of each should be used to obtain 100 milliliters of a 68% solution? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " x + y = 100, (1) (total mass equation)\r\n" ); document.write( "0.5x + 0.8y = 0.68*100. (2) (hydrochloric acid content equation)\r\n" ); document.write( "\r\n" ); document.write( "or\r\n" ); document.write( "\r\n" ); document.write( " x + y = 100, (1')\r\n" ); document.write( "0.5x + 0.8y = 68. (2')\r\n" ); document.write( "\r\n" ); document.write( "Express y = 100 - x from (1') and substitute it into (2').\r\n" ); document.write( "\r\n" ); document.write( "Then solve the obtained equation for x.\r\n" ); document.write( "\r\n" ); document.write( "After finding x, substitute it into (1) and solve for y.\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |