document.write( "Question 89006: You scored 88.7, 91.2, and 94.6 on your last three test scores. Find the standard deviation of your test scores.
\n" ); document.write( "A. 0.95
\n" ); document.write( "B.1.22
\n" ); document.write( "C.2.42
\n" ); document.write( "D.4.35\r
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Algebra.Com's Answer #64694 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First lets find the mean:\r
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\n" ); document.write( "\n" ); document.write( "To find the mean, add up all of the numbers and divide the sum by the number of numbers (which in this case is 3).\r
\n" ); document.write( "\n" ); document.write( "\"Mean=%2888.7%2B+91.2%2B+94.6+%29%2F3=274.5%2F3=91.5\"\r
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\n" ); document.write( "\n" ); document.write( "So the mean is 91.5\r
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\n" ); document.write( "\n" ); document.write( "Use this formula to find the standard deviation:\r
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\n" ); document.write( "\n" ); document.write( "Standard Deviation: where is the mean, is the ith number, and is the number of numbers\r
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\n" ); document.write( "\n" ); document.write( "So we can replace N with 3\r
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\n" ); document.write( "\n" ); document.write( "Replace with 91.5\r
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\n" ); document.write( "\n" ); document.write( "Expand the summation (replace each \"x%5Bi%5D\" with the respective number)\r
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\n" ); document.write( "\n" ); document.write( "Subtract the terms in the parenthesis\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28%281%2F3%29%28%28-2.8%29%5E2%2B%28-0.3%29%5E2%2B%283.1%29%5E2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Square each term\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28%281%2F3%29%287.84%2B0.09%2B9.61%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Add up all of the terms\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28%281%2F3%2917.54%29\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%285.84666666666667%29\" \r
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\n" ); document.write( "\n" ); document.write( "Take the square root\r
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\n" ); document.write( "\n" ); document.write( "\"2.41798814444295\"\r
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\n" ); document.write( "\n" ); document.write( "So the standard deviation is \"2.41798814444295\"\r
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\n" ); document.write( "\n" ); document.write( "So if you round to the nearest hundredth, you get 2.42. So the answer is C)
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