document.write( "Question 1032176: What is the probability of obtaining a sum of at least eight when rolling a pair of dice? \n" ); document.write( "
Algebra.Com's Answer #646910 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Here are all 36 dice rolls:\r\n" ); document.write( " \r\n" ); document.write( "(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)\r\n" ); document.write( "\r\n" ); document.write( "(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) \r\n" ); document.write( "\r\n" ); document.write( "(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) \r\n" ); document.write( "\r\n" ); document.write( "(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) \r\n" ); document.write( "\r\n" ); document.write( "(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) \r\n" ); document.write( "\r\n" ); document.write( "(6,1) (6,2) (6,3) (6,4) (6,5) (6,6) \r\n" ); document.write( "\r\n" ); document.write( "The ones colored red have sum 8 or more.\r\n" ); document.write( "\r\n" ); document.write( "Count them. There are 15 of them. So the \r\n" ); document.write( "probability that you want is 15 times out\r\n" ); document.write( "of 36, which is the fraction 15/36 which\r\n" ); document.write( "reduces to 5/12.\r\n" ); document.write( "\r\n" ); document.write( "That means that five times out of twelve you can expect\r\n" ); document.write( "to roll a sum of 8 or higher. That is almost 42% of the\r\n" ); document.write( "time.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |