document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032259>Question 1032259</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The function f(x)=x^2-10x+21 has a maximum value or a minimum value and determine the value. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646893 by </B><A HREF=/tutors/aboutme.mpl?userid=adunbar><B>adunbar(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=adunbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=adunbar><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The function has f'(x) = 2x-10 = 0 at the maximum / minimum point.<BR>\n" );
document.write( "That means, 2x = 10 so x = 5, hence, y = 5^2 - 10*5 + 21 = 25-50+21 = -4<BR>\n" );
document.write( "The max / min is at (5, -4)<BR>\n" );
document.write( "f''(x) = 2 > 0 Therefore is a minimum  </SPAN>\n" );
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