document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032197>Question 1032197</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Briana uses the following equation to model the number of infected people each week.<BR>\n" );
document.write( "Y=50 e^0.3t.     Y represents the number of infected people and t represents time in weeks. In how many weeks will the number of infected people reach 2500. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646853 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "Y=50 e^0.3t.<BR>\n" );
document.write( "In how many weeks will the number <BR>\n" );
document.write( "of infected people reach 2500?<BR>\n" );
document.write( "50 e^0.3t = 2,500<BR>\n" );
document.write( "e^0.3t = 2,500/50<BR>\n" );
document.write( "e^0.3t = 50<BR>\n" );
document.write( "0.3t loge e = loge(50)<BR>\n" );
document.write( "(loge e = 1)<BR>\n" );
document.write( "0.3t = loge (50)<BR>\n" );
document.write( "t = loge (50)/0.3<BR>\n" );
document.write( "t = 13.04 weeks<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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