document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032162>Question 1032162</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the given information to determine the exact trigonometric value.<BR>\n" );
document.write( "If cos(theta)=4/5 and 270 degrees < theta < 360 degrees, find the exact value of sin(2theta) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646808 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646808\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the given information to determine the exact trigonometric value.<BR>\n" );
document.write( "If cos(theta) = 4/5 and 270 degrees < theta < 360 degrees, <BR>\n" );
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document.write( "Since cos = x/r, x = 4 and r = 5<BR>\n" );
document.write( "Then y = sqrt(r^2-x^2) = sqrt(25-16) = 3<BR>\n" );
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document.write( "Since t is in QIII, y is negative 3<BR>\n" );
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document.write( "So sin(t) = -3/5<BR>\n" );
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document.write( "\n" );
document.write( "find the exact value of sin(2theta) = 2*sin(t)*cos(t) = 2(-3/5)(4/5) = -24/25<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "-------------  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );