document.write( "Question 1032113: Jane ans Jill live 13.5 km apart. At 10:00 AM each girl leaves her house and jogs toward the other. The ratio of Jane's speed to Jill's is 5:4. If the girls meet at 11:15 AM, how fast does each jog? Give Rate, Time, and distance for each girl. \n" ); document.write( "
Algebra.Com's Answer #646806 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Jane and Jill live 13.5 km apart.\r \n" ); document.write( "\n" ); document.write( "d=13.5 km\r \n" ); document.write( "\n" ); document.write( "The ratio of Jane's speed to Jill's is 5:4. \n" ); document.write( "let common multiple be x \n" ); document.write( "Jane's speed =5x \n" ); document.write( "Jill's speed =4x. \r \n" ); document.write( "\n" ); document.write( " At 10:00 AM each girl leaves her house and jogs toward the other. If the girls meet at 11:15 AM,\r \n" ); document.write( "\n" ); document.write( "time = 1 1/4 hour => 5/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "time = 13.5/(5x+4x)\r \n" ); document.write( "\n" ); document.write( "5/4 = 13.5/9x\r \n" ); document.write( "\n" ); document.write( "45x = 54\r \n" ); document.write( "\n" ); document.write( "x= 6/5\r \n" ); document.write( "\n" ); document.write( "5x = 5*6/5 = 6 km/h=> jane\r \n" ); document.write( "\n" ); document.write( "distance = 6*1.25 = 7.50 km\r \n" ); document.write( "\n" ); document.write( "4x = 4*6/5 = 4.8 km/h => Jill \n" ); document.write( "distance = 1,25*4.8 =6 km\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " how fast does each jog? Give Rate, Time, and distance for each girl. \n" ); document.write( " |