document.write( "Question 1031982: solve the inequality of |3x+1|<2+|2x+3| \n" ); document.write( "
Algebra.Com's Answer #646771 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Re-write so that the inequality can be decomposed into a piece-wise function:\r
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\n" ); document.write( "\n" ); document.write( "This inequality has two critical points; values that make one of the expressions inside of the absolute value bars equal to zero, namely and \r
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\n" ); document.write( "\n" ); document.write( "Hence there are three intervals to consider when creating a piece-wise function definition: and \r
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\n" ); document.write( "\n" ); document.write( "Since and when , we can say:\r
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\n" ); document.write( "\n" ); document.write( " if \r
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\n" ); document.write( "\n" ); document.write( "So we need to find the interval that satisfies both and \r
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\n" ); document.write( "\n" ); document.write( "\ 0\">.\r
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\n" ); document.write( "\n" ); document.write( "But the intervals and are disjoint. Hence, there is no part of the solution set in the interval .\r
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\n" ); document.write( "\n" ); document.write( "Next, for values in ,\r
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\n" ); document.write( "\n" ); document.write( "So, set the function less than zero and solve:\r
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\n" ); document.write( "\n" ); document.write( "\ -\frac{6}{5}\">\r
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\n" ); document.write( "\n" ); document.write( "Hence, the function is true on the interval \r
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\n" ); document.write( "\n" ); document.write( "Finally, for values in \r
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\n" ); document.write( "\n" ); document.write( "\ 4\">\r
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\n" ); document.write( "\n" ); document.write( "So the inequality holds for values in the interval \r
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\n" ); document.write( "\n" ); document.write( "That leaves the value to check which we can do in the original inequality:\r
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\n" ); document.write( "\n" ); document.write( "So now we can specify the union of the two valid intervals which include the endpoint, and \r
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\n" ); document.write( "\n" ); document.write( "Is the complete solution set interval.\r
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\n" ); document.write( "\n" ); document.write( "Compare this result to the portion of the graph of that is below the -axis.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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