document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88947>Question 88947</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars are leaving Phils house at precisely 6:20 PM.  The first car, driven by Phil is headed north.  The second car, driven by Roman, is headed south.  Phil, because he is not a good citizen, is going 20 MPH faster than Roman.  If, at 7:50, they are exactly 168 miles apart, how fast is each going? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64675 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> BOTH CARS TRAVEL FOR 1.5 HOURS. THERE SPEEDS ARE X & (X+20). THEIR TOTAL DISTANCE IS 168 MILES THUS WE HAVE THE FOLLOWING FORMULA:<BR>\n" );
document.write( "1.5X+1.5(X+20)=168<BR>\n" );
document.write( "1.5X+1.5X+30=168<BR>\n" );
document.write( "3X=168-30<BR>\n" );
document.write( "3X=138<BR>\n" );
document.write( "X=138/3<BR>\n" );
document.write( "X=46 MPH FOR THE SLOWER DRIVER.<BR>\n" );
document.write( "46+20=66 MPH FOR THE FASTER DRIVER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "1.5*46+1.5*66=168<BR>\n" );
document.write( "69+99=168<BR>\n" );
document.write( "168=168\r<BR>\n" );
document.write( "\n" );
document.write( " <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );