document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1032038>Question 1032038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mixture contains alcohol and water in the ratio of 12:5, on adding 14 litres of wate, the ratio of alcohol to water becomes 4:3. The quality of alcohol in the mixture is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #646739 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=646739\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Doing as volume parts, alcohol : water,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2812%2F17%29%2As%2F%28s%2B14%29=4%2F7 ALIGN=MIDDLE  ALT=\"%2812%2F17%29%2As%2F%28s%2B14%29=4%2F7\"   DISABLED_style= \"max-width:90%; height:auto;\" > using s for quantity of the starting mixture.  The proportion here presented is parts per mixture, numerator being the parts as alcohol.\r<BR>\n" );
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document.write( "The question asked for \"quality\" of the alcohol in the mixture.  A more sensible question would be, what QUANTITY of the 12:5 MIXTURE was used to prepare the 4:3 alcohol-to-water mixture.  Solving for s will give that answer. </SPAN>\n" );
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